2A$7$?3d9g$,9b$/$J$C$F$$$k$3$H$,J,$+$k!%(B
$BDs0F2A$7$?Nc$rI=(B6.4($BF|1QK]Lu$NC1J8(B)$B!$I=(B6.5($BF|1QK]Lu(B
$B$N=EJ8J#J8(B)$B!$I=(B6.6($B1QF|K]Lu$NC1J8(B)$B!$I=(B6.7($B1QF|K]Lu$N=EJ8J#J8(B)$B$K<($9!%(B
$BI=(B 6.4:
$BBPHf3S2A$7$?Nc(B($BF|1QK]Lu$NC1J8(B)
=3cm
|
$BDs0F
$BI=(B 6.5:
$BBPHf3S2A$7$?Nc(B($BF|1QK]Lu$N=EJ8J#J8(B)
=1cm
|
$BDs0F
$BI=(B 6.6:
$BBPHf3S2A$7$?Nc(B($B1QF|K]Lu$NC1J8(B)
=2.5cm
|
$BDs0F
$BI=(B 6.7:
$BBPHf3S2A$7$?Nc(B($B1QF|K]Lu$N=EJ8J#J8(B)
=0.06cm
|
$BDs0F
$BDs0F2A$7$?Nc$rI=(B6.8($BF|1QK]Lu$NC1J8(B)$B!$I=(B6.9($BF|1QK]Lu(B
$B$N=EJ8J#J8(B)$B!$I=(B6.10($B1QF|K]Lu$NC1J8(B)$B!$I=(B6.11($B1QF|K]Lu$N=EJ8J#J8(B)$B$K<($9!%(B
$BI=(B 6.8:
$BBPHf3S2A$7$?Nc(B($BF|1QK]Lu$NC1J8(B)
=2.5cm
|
$BDs0F
$BI=(B 6.9:
$BBPHf3S2A$7$?Nc(B($BF|1QK]Lu$N=EJ8J#J8(B)
=1cm
|
$BDs0F
$BI=(B 6.10:
$BBPHf3S2A$7$?Nc(B($B1QF|K]Lu$NC1J8(B)
=1.2cm
|
$BDs0F
$BI=(B 6.11:
$BBPHf3S2A$7$?Nc(B($B1QF|K]Lu$N=EJ8J#J8(B)
=1cm
|
$BDs0F
$B $B9M;!(B
$B>e$X(B: $BK]LuBP$NK]Lu3NN($N=E$_$N:GE,2=(B
$BLa$k(B: $BK]Lu
$BL\
$BJ?@.(B21$BG/(B3$B7n(B17$BF|(B